top of page
Analysis of Variance (ANOVA)

Analysis of Variance (ANOVA) is a statistical method used within the framework of Lean Six Sigma for hypothesis testing with normal data. This method is particularly useful in the context of Parametric Tests for Normal Data, which assumes that the data follows a normal distribution. ANOVA is employed to determine if there are any statistically significant differences between the means of three or more independent (unrelated) groups. Its application spans various industries and disciplines, aiding in the improvement of processes, quality control, and decision-making.

The Basics of ANOVA

ANOVA tests the null hypothesis, which typically states that all groups are samples from populations with the same mean. In contrast, the alternative hypothesis suggests that at least one group is different. The essence of ANOVA is to analyze the variances within groups compared to the variance between groups to identify any significant differences. This is achieved by dividing the total variance observed in the data into components attributable to different sources of variation.

Types of ANOVA

  1. One-Way ANOVA: Used when comparing the means of three or more groups based on one independent variable. For example, testing if the average defect rates of products differ by supplier.

  2. Two-Way ANOVA: This method is employed when analyzing the effect of two independent variables on a dependent variable. It can also assess the interaction effect between the two independent variables.

  3. Repeated Measures ANOVA: Applied when the same subjects are used in all groups, allowing for the comparison of means across different times or conditions.

Assumptions of ANOVA

ANOVA relies on several key assumptions:

  • Normality: The data in each group should be approximately normally distributed.

  • Homogeneity of Variances: The variance among the groups should be roughly equal.

  • Independence: The observations must be independent of each other.

Violations of these assumptions may necessitate the use of different statistical methods or transformations of the data.

Steps in Conducting ANOVA

  1. Formulate Hypotheses: Define the null and alternative hypotheses.

  2. Calculate ANOVA Statistics: Determine the between-group and within-group variances and compute the F-statistic.

  3. Determine Significance: Compare the calculated F-statistic against critical values from F-distribution tables or use a p-value to decide on the null hypothesis.

  4. Post-Hoc Testing: If significant differences are found, further analysis with post-hoc tests may be needed to identify which specific groups differ.


Importance in Lean Six Sigma

In Lean Six Sigma projects, ANOVA is invaluable for identifying factors that significantly affect process performance or quality characteristics. By understanding these factors, businesses can focus their improvement efforts more effectively, leading to enhanced process efficiency, reduced variability, and increased customer satisfaction.


Conclusion

Analysis of Variance (ANOVA) is a powerful tool in the Lean Six Sigma toolkit for testing differences between group means under the assumption of normality. By applying ANOVA, practitioners can make informed decisions based on statistical evidence, driving improvements in quality and process performance. Its ability to dissect and analyze the sources of variation makes it an essential technique for any quality improvement initiative.


Scenario: Employee Productivity Analysis

A company wants to evaluate the effectiveness of three different training programs (A, B, and C) on employee productivity. Productivity scores (higher scores mean better productivity) are measured after employees have completed their respective training programs. The company aims to determine if there's a significant difference in productivity across these training programs.


Data

Here's the productivity score for 4 employees from each training program:

  • Training Program A: 85, 88, 90, 87

  • Training Program B: 80, 83, 85, 82

  • Training Program C: 92, 95, 93, 94


Step 1: Calculate the Overall Mean Yˉ

(85 + 88 + 90 + 87 + 80 + 83 + 85 + 82 + 92 + 95 + 93 + 94) / 12 = Yˉ = 87.83


Step 2: Calculate the Sum of Squares Between Groups (SSB)

Therefore, the SSB, or the Sum of Squares Between Groups, with our given data is approximately 242.67.



Step 3: Calculate the Sum of Squares Within Groups (SSW)


For Training Program A:

  • Training Program A: [85, 88, 90, 87]

  • Mean of Training Program A (YˉA) = 87.5


For Training Program B:

  • Training Program B: [80, 83, 85, 82]

  • Mean of Training Program B (YˉB) = 82.5


For Training Program C:

  • Training Program C: [92, 95, 93, 94]

  • Mean of Training Program C (YˉC) = 93.5


Total SSW:


Thus, the Sum of Squares Within Groups (SSW) with our example data is 31.


Step 4: Calculate the Mean Square Between Groups (MSB) and Mean Square Within Groups (MSW)

For Step 4, we calculate the Mean Square Between Groups (MSB) and the Mean Square Within Groups (MSW) based on our previous calculations of Sum of Squares Between Groups (SSB) and Sum of Squares Within Groups (SSW).

Given:

SSB = 242.67

SSW = 31

k (number of groups) = 3

N (total number of observations) = 12

n (number of observations per group) = 4


Mean Square Between Groups (MSB):


Mean Square Within Groups (MSW):

Results:

  • The Mean Square Between Groups (MSB) is approximately 121.335.

  • The Mean Square Within Groups (MSW) is approximately 3.444.


Step 5: Calculate the F-statistic

The F-statistic is calculated as:

Substituting our values:


F≈35.226


Step 6: Find the critical value


To find the critical value in an F-distribution table for our scenario, you need two pieces of information: the degrees of freedom for the numerator (df1) and the degrees of freedom for the denominator (df2). In our case:

  • df1 (degrees of freedom between groups) k−1=3−1=2.

  • df2 (degrees of freedom within groups) Nk=12−3=9.

  • With an alpha level (α) commonly set at 0.05 for significance testing, you would look up the critical value in the F-distribution table that corresponds to df1 = 2 and df2 = 9.

The critical value in the F-distribution for df1 = 2, df2 = 9, and an alpha level of 0.05 is approximately 4.256.

Interpretation of Results

This means that if your calculated F-statistic is greater than 4.256, you can reject the null hypothesis and conclude that there is a statistically significant difference in means among the groups at the 0.05 significance level. Our calculated F-statistic of approximately 35.226 far exceeds this threshold, indicating significant differences among the training programs' productivity scores. ​


Videos






Curent Location

/412

Article

Rank:

Analysis of Variance (ANOVA)

309

Section:

LSS_BoK_3.4 - Hypothesis Testing with Normal Data

F) Parametric Tests for Normal Data

Sub Section:

Previous article:

Next article:

bottom of page